Webderivative of (u⁻¹) = −u⁻² du Back substituting: = − (cos x)⁻² ( − sin x) ∙ dx = [sin x / (cos x)²] ∙ dx = [ (sin x / cos x) ∙ (1/cos x)] ∙ dx = [tan (x) ∙ sec (x)] ∙ dx 5 comments ( 10 votes) Upvote Downvote Flag more Joseph Mandes 9 years ago I think I understand how to do the derivatives of the trig functions. But What if instead of Sin (x, Webderivative of sec^2(x) Natural Language; Math Input; Extended Keyboard Examples Upload Random. Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music…
finding derivative of g (x) = xtanx - Mathematics Stack …
WebThe Derivative Calculator lets you calculate derivatives of functions online — for free! Our calculator allows you to check your solutions to calculus exercises. It helps you practice … WebLet y=xtanx/ (sinx+cosx). After rearranging, ysinx + ycosx = xtanx Differentiating both sides and using multiplication rule i.e (xy)'=xy'+yx' y' sinx+ ycosx +y'cosx - ysinx = tanx + sec^2 (x) After doing simple algebraic rearrangment we will get: y'= (tanx + xsec^2 (x) - xtanx.cos2x)/ (sinx+cosx) Hope this helps. touchstone crystals photos
Differentiate: xtanx(secx + tanx) - Toppr
WebDec 1, 2016 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos (x) and y=tan (x) 1 Answer Noah G Dec 1, 2016 dy dx = sinx − cosx (sinx + cosx)2 Explanation: First of all, I'm assuming the function is y = secx 1 + tanx? Call your function f (x). f (x) = secx 1 + tanx f (x) = 1 cosx 1 + sinx cosx f (x) = 1 cosx cosx+sinx cosx WebThe first derivative of \( \tan (x)\) is calculated using the derivative of \( \sin x \) and \( \cos x \) and the quotient rule of derivatives. Calculation of the Derivative of tan x WebNov 10, 2016 · Calculus Differentiating Trigonometric Functions Derivatives of y=sec (x), y=cot (x), y= csc (x) 1 Answer Steve M Nov 10, 2016 f '(x) = (1 + xtanx)secx Explanation: If you are studying maths, then you should learn the Product Rule for Differentiation, and practice how to use it: d dx (uv) = u dv dx + du dx v, or, (uv)' = (du)v +u(dv) potter thesaurus